What is the derivative of f(x)=x^3+1 ?

The derivative of f(x)=x^3+1 is 3x^2

What is the first derivative of f(x)=x^3+1 ?

The first derivative of f(x)=x^3+1 is 3x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{3} + 1

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{8 x}{3}

\frac{- 1}{( s - 1 ) ^{2}}

y = x^{3} + 4 x^{2} + 5 x + 7

cos^{2} (x) + sin (x)

x + 11

What is the derivative of f(x)=x^3+1 ?
The derivative of f(x)=x^3+1 is 3x^2
What is the first derivative of f(x)=x^3+1 ?
The first derivative of f(x)=x^3+1 is 3x^2