What is the derivative of-2+3sin(x) ?

The derivative of-2+3sin(x) is 3cos(x)

What is the first derivative of-2+3sin(x) ?

The first derivative of-2+3sin(x) is 3cos(x)

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derivative of

- 2 + 3 sin (x)

3 cos (x)

Solution steps

\frac{d}{d x} (- 2 + 3 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2) + \frac{d}{d x} (3 sin (x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

= - 0 + 3 cos (x)

Simplify

= 3 cos (x)

\frac{x ^{2} - x - 2}{∣ x - 2 ∣}

\frac{( a + 2 )}{( a + x )}

\frac{d}{d p} (20 p)

m (t) = 20 e^{0.8} t

x + 3 g

What is the derivative of-2+3sin(x) ?
The derivative of-2+3sin(x) is 3cos(x)
What is the first derivative of-2+3sin(x) ?
The first derivative of-2+3sin(x) is 3cos(x)