What is the integral of (3x-sin(x)) ?

The integral of (3x-sin(x)) is (3x^2)/2+cos(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x-sin(x))

\int (3 x - sin (x)) d x

\frac{3 x ^{2}}{2} + cos (x) + C

Solution steps

\int 3 x - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int sin (x) d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int sin (x) d x = - cos (x)

= \frac{3 x ^{2}}{2} - (- cos (x))

Simplify

= \frac{3 x ^{2}}{2} + cos (x)

Add a constant to the solution

= \frac{3 x ^{2}}{2} + cos (x) + C

\frac{\partial}{\partial y} (2 x^{3} y - 3)

\frac{5 X ^{4} - 3 X ^{3}}{X ^{5}}

\frac{d ^{4}}{d x ^{4}} (9 e^{x^{2}})

100

x \to 7 lim (\frac{\frac{1}{x} - \frac{1}{7}}{x - 7})

What is the integral of (3x-sin(x)) ?
The integral of (3x-sin(x)) is (3x^2)/2+cos(x)+C