What is the d/(dt)(asin(t)+1) ?

The d/(dt)(asin(t)+1) is acos(t)

What is the first d/(dt)(asin(t)+1) ?

The first d/(dt)(asin(t)+1) is acos(t)

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\frac{d}{d t} (a sin (t) + 1)

a cos (t)

Solution steps

\frac{d}{d t} (a sin (t) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a sin (t)) + \frac{d}{d t} (1)

\frac{d}{d t} (a sin (t)) = a cos (t)

\frac{d}{d t} (1) = 0

= a cos (t) + 0

Simplify

= a cos (t)

3 cos^{- 3} (x)

(5 x^{9} + 7 x^{2} - 65)^{- 9}

2^{x} - 1

1 - x^{2} - ln (x)

\frac{100}{x ^{2}}