What is the derivative of y=log_{4}(x^2) ?

The derivative of y=log_{4}(x^2) is 1/(ln(2)x)

What is the first derivative of y=log_{4}(x^2) ?

The first derivative of y=log_{4}(x^2) is 1/(ln(2)x)

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derivative of

y = lo g_{4} (x^{2})

\frac{1}{ln ( 2 ) x}

Solution steps

\frac{d}{d x} (lo g_{4} (x^{2}))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= \frac{d}{d x} (\frac{ln ( x ^{2} )}{ln ( 4 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 4 )} \frac{d}{d x} (ln (x^{2}))

Apply the chain rule:

\frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

= \frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{ln ( 4 )} \cdot \frac{1}{x ^{2}} \cdot 2 x

Simplify

\frac{1}{ln ( 4 )} \cdot \frac{1}{x ^{2}} \cdot 2 x : \frac{1}{ln ( 2 ) x}

= \frac{1}{ln ( 2 ) x}

cos (x - 2 5^{\circ})

f (x) = [x - \frac{1}{x}]^{2}

(x^{\frac{1}{2}})^{2}

\frac{x}{( x ^{2} + 1 ) ^{2}}

5 sin (x \cdot y)

What is the derivative of y=log_{4}(x^2) ?
The derivative of y=log_{4}(x^2) is 1/(ln(2)x)
What is the first derivative of y=log_{4}(x^2) ?
The first derivative of y=log_{4}(x^2) is 1/(ln(2)x)