What is the first derivative of 3x+y ?

The first derivative of 3x+y is 3

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derivative of 3x+y

derivative of

3 x + y

3

Solution steps

\frac{d}{d x} (3 x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d y}{d x}

\frac{d}{d x} (3 x) = 3

\frac{d y}{d x} = 0

= 3 + 0

Simplify

= 3

\frac{2 x}{( x ^{2} + y ^{2} )}

sec^{3} (\frac{x}{2})

\frac{1}{( 2 x + 2 )}

lo g_{10} (x^{6} + 5)

y = (x + a)^{3}