What is the first derivative of y=2t^2 ?

The first derivative of y=2t^2 is 4t

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derivative of y=2t^2

derivative of

y = 2 t^{2}

4 t

Solution steps

\frac{d}{d t} (2 t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 t^{2 - 1}

Simplify

= 4 t

\frac{x}{( x ^{2} + 4 )}

(2 x + 3)^{5}

\frac{( x - 1 ) ^{2}}{x - 2}

(a + 2 x)^{7 x}

\frac{1 - t ^{4}}{4}