What is the derivative of (x/3)^2 ?

The derivative of (x/3)^2 is (2x)/9

What is the first derivative of (x/3)^2 ?

The first derivative of (x/3)^2 is (2x)/9

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derivative of

(\frac{x}{3})^{2}

\frac{2 x}{9}

Solution steps

\frac{d}{d x} ((\frac{x}{3})^{2})

Apply the chain rule:

2 \cdot \frac{x}{3} \frac{d}{d x} (\frac{x}{3})

= 2 \cdot \frac{x}{3} \frac{d}{d x} (\frac{x}{3})

\frac{d}{d x} (\frac{x}{3}) = \frac{1}{3}

= 2 \cdot \frac{x}{3} \cdot \frac{1}{3}

Simplify

2 \cdot \frac{x}{3} \cdot \frac{1}{3} : \frac{2 x}{9}

= \frac{2 x}{9}

6 cos (x) + sin^{2} (x)

\frac{d}{d a} (cos^{4} (a) - sin^{4} (a) + 1)

ln (sin^{2} (e^{x}))

y = sin (\frac{x}{2})

\frac{e ^{- 1}}{x ^{4}}

What is the derivative of (x/3)^2 ?
The derivative of (x/3)^2 is (2x)/9
What is the first derivative of (x/3)^2 ?
The first derivative of (x/3)^2 is (2x)/9