What is the derivative of 6/(2-4x) ?

The derivative of 6/(2-4x) is 6/((2x-1)^2)

What is the first derivative of 6/(2-4x) ?

The first derivative of 6/(2-4x) is 6/((2x-1)^2)

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derivative of

\frac{6}{2 - 4 x}

\frac{6}{( 2 x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6}{2 - 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{2 - 4 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((2 - 4 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 - 4 x ) ^{2}} \frac{d}{d x} (2 - 4 x)

= - \frac{1}{( 2 - 4 x ) ^{2}} \frac{d}{d x} (2 - 4 x)

\frac{d}{d x} (2 - 4 x) = - 4

= 6 (- \frac{1}{( 2 - 4 x ) ^{2}} (- 4))

Simplify

6 (- \frac{1}{( 2 - 4 x ) ^{2}} (- 4)) : \frac{6}{( 2 x - 1 ) ^{2}}

= \frac{6}{( 2 x - 1 ) ^{2}}

\frac{- 1}{( x + 1 ) ^{2}}

\frac{50}{( x + 5 )}

\frac{( ( x ) sin ( x ) )}{( x + 1 )}

y = (2 x - 1) a^{x}

y = 4 x^{3} - 4 x^{2} + x - 1

What is the derivative of 6/(2-4x) ?
The derivative of 6/(2-4x) is 6/((2x-1)^2)
What is the first derivative of 6/(2-4x) ?
The first derivative of 6/(2-4x) is 6/((2x-1)^2)