What is the derivative of b(1-sin(x)) ?

The derivative of b(1-sin(x)) is -bcos(x)

What is the first derivative of b(1-sin(x)) ?

The first derivative of b(1-sin(x)) is -bcos(x)

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derivative of

b (1 - sin (x))

- b cos (x)

Solution steps

\frac{d}{d x} (b (1 - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (1 - sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= b (\frac{d}{d x} (1) - \frac{d}{d x} (sin (x)))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (x)) = cos (x)

= b (0 - cos (x))

Simplify

= - b cos (x)

cot (x^{2} sin^{2} (x))

a^{3}

y = (\frac{x + 2}{x}) (\frac{x ^{2} - 1}{x})

\frac{4 cos ^{2} ( x )}{sin ^{2} ( x )}

\frac{( x + 4 )}{( ( 2 x + 3 ) ( x + 1 ) )}

What is the derivative of b(1-sin(x)) ?
The derivative of b(1-sin(x)) is -bcos(x)
What is the first derivative of b(1-sin(x)) ?
The first derivative of b(1-sin(x)) is -bcos(x)