What is the derivative of (x^3-1)^3 ?

The derivative of (x^3-1)^3 is 9x^2(x^3-1)^2

What is the first derivative of (x^3-1)^3 ?

The first derivative of (x^3-1)^3 is 9x^2(x^3-1)^2

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derivative of

(x^{3} - 1)^{3}

9 x^{2} (x^{3} - 1)^{2}

Solution steps

\frac{d}{d x} ((x^{3} - 1)^{3})

Apply the chain rule:

3 (x^{3} - 1)^{2} \frac{d}{d x} (x^{3} - 1)

= 3 (x^{3} - 1)^{2} \frac{d}{d x} (x^{3} - 1)

\frac{d}{d x} (x^{3} - 1) = 3 x^{2}

= 3 (x^{3} - 1)^{2} \cdot 3 x^{2}

Simplify

= 9 x^{2} (x^{3} - 1)^{2}

\frac{sin ( x )}{x ^{2}}

e^{2} + (sec (x) x)

\frac{d}{dd} (10 d)

\frac{d}{d t} (3 sin (314 t) + 4 cos (314 t))

(x^{18})^{x}

What is the derivative of (x^3-1)^3 ?
The derivative of (x^3-1)^3 is 9x^2(x^3-1)^2
What is the first derivative of (x^3-1)^3 ?
The first derivative of (x^3-1)^3 is 9x^2(x^3-1)^2