What is the derivative of y=6x^2-3x^3 ?

The derivative of y=6x^2-3x^3 is 12x-9x^2

What is the first derivative of y=6x^2-3x^3 ?

The first derivative of y=6x^2-3x^3 is 12x-9x^2

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derivative of

y = 6 x^{2} - 3 x^{3}

12 x - 9 x^{2}

Solution steps

\frac{d}{d x} (6 x^{2} - 3 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (3 x^{3})

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

= 12 x - 9 x^{2}

y = (5 x - 3) (\frac{4 x - 3}{x})

\frac{- 5}{( 4 x - 2 y + 2 )}

y = 5 x^{8} - 6 x + 12

f (t) = 3 + 8 t - t^{2}

y = x^{2} + 5

What is the derivative of y=6x^2-3x^3 ?
The derivative of y=6x^2-3x^3 is 12x-9x^2
What is the first derivative of y=6x^2-3x^3 ?
The first derivative of y=6x^2-3x^3 is 12x-9x^2