What is the derivative of 2x^2-x+1 ?

The derivative of 2x^2-x+1 is 4x-1

What is the first derivative of 2x^2-x+1 ?

The first derivative of 2x^2-x+1 is 4x-1

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derivative of

2 x^{2} - x + 1

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 4 x - 1 + 0

Simplify

= 4 x - 1

y = 2 x^{2} + 3 x \cdot tan (x)

f (x) = 10 - 5 x

64 (2 + x)^{1}

e^{- 0} 0.25 x

e^{l} o gx + 1

What is the derivative of 2x^2-x+1 ?
The derivative of 2x^2-x+1 is 4x-1
What is the first derivative of 2x^2-x+1 ?
The first derivative of 2x^2-x+1 is 4x-1