What is the derivative of (4x^3+2)/x ?

The derivative of (4x^3+2)/x is (8x^3-2)/(x^2)

What is the first derivative of (4x^3+2)/x ?

The first derivative of (4x^3+2)/x is (8x^3-2)/(x^2)

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derivative of

\frac{4 x ^{3} + 2}{x}

\frac{8 x ^{3} - 2}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{3} + 2}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{3} + 2 ) x - \frac{d x}{d x} ( 4 x ^{3} + 2 )}{x ^{2}}

\frac{d}{d x} (4 x^{3} + 2) = 12 x^{2}

\frac{d x}{d x} = 1

= \frac{12 x ^{2} x - 1 \cdot ( 4 x ^{3} + 2 )}{x ^{2}}

Simplify

\frac{12 x ^{2} x - 1 \cdot ( 4 x ^{3} + 2 )}{x ^{2}} : \frac{8 x ^{3} - 2}{x ^{2}}

= \frac{8 x ^{3} - 2}{x ^{2}}

\frac{d}{d b} (\frac{( 1 + sin ( b ) )}{( 1 - sin ( b ) )})

y = \frac{x}{( x + 2 )}

- 2 y^{2}

ln (x^{4} + 3)

ln (\frac{x + 1}{x})

What is the derivative of (4x^3+2)/x ?
The derivative of (4x^3+2)/x is (8x^3-2)/(x^2)
What is the first derivative of (4x^3+2)/x ?
The first derivative of (4x^3+2)/x is (8x^3-2)/(x^2)