What is the derivative of 2/3 (x^4)/6+5(x^4)/5 ?

The derivative of 2/3 (x^4)/6+5(x^4)/5 is (40x^3)/9

What is the first derivative of 2/3 (x^4)/6+5(x^4)/5 ?

The first derivative of 2/3 (x^4)/6+5(x^4)/5 is (40x^3)/9

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derivative of

\frac{2}{3} \frac{x ^{4}}{6} + 5 \frac{x ^{4}}{5}

\frac{40 x ^{3}}{9}

Solution steps

\frac{d}{d x} (\frac{2}{3} \cdot \frac{x ^{4}}{6} + 5 \cdot \frac{x ^{4}}{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{3} \cdot \frac{x ^{4}}{6}) + \frac{d}{d x} (5 \cdot \frac{x ^{4}}{5})

\frac{d}{d x} (\frac{2}{3} \cdot \frac{x ^{4}}{6}) = \frac{4 x ^{3}}{9}

\frac{d}{d x} (5 \cdot \frac{x ^{4}}{5}) = 4 x^{3}

= \frac{4 x ^{3}}{9} + 4 x^{3}

Simplify

\frac{4 x ^{3}}{9} + 4 x^{3} : \frac{40 x ^{3}}{9}

= \frac{40 x ^{3}}{9}

e^{l} o gx + 1

y = (2 t - 3)^{2}

\frac{2 x}{( 1 - x ^{2} ) ^{2}}

10 + x

1 2^{0.5} - x^{1.5}

What is the derivative of 2/3 (x^4)/6+5(x^4)/5 ?
The derivative of 2/3 (x^4)/6+5(x^4)/5 is (40x^3)/9
What is the first derivative of 2/3 (x^4)/6+5(x^4)/5 ?
The first derivative of 2/3 (x^4)/6+5(x^4)/5 is (40x^3)/9