What is the derivative of x^3+2x^2+4 ?

The derivative of x^3+2x^2+4 is 3x^2+4x

What is the first derivative of x^3+2x^2+4 ?

The first derivative of x^3+2x^2+4 is 3x^2+4x

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derivative of

x^{3} + 2 x^{2} + 4

3 x^{2} + 4 x

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4) = 0

= 3 x^{2} + 4 x + 0

Simplify

= 3 x^{2} + 4 x

3 x^{4} + 6 x^{2} + 8

2 x - e^{4 x^{2}}

(3 x)^{2}

\frac{( 3 x ^{2} - 1 )}{( x + 1 ) ^{3}}

sin^{2} (2 x + 5)

What is the derivative of x^3+2x^2+4 ?
The derivative of x^3+2x^2+4 is 3x^2+4x
What is the first derivative of x^3+2x^2+4 ?
The first derivative of x^3+2x^2+4 is 3x^2+4x