What is the derivative of x^x-100 ?

The derivative of x^x-100 is x^x(ln(x)+1)

What is the first derivative of x^x-100 ?

The first derivative of x^x-100 is x^x(ln(x)+1)

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derivative of

x^{x} - 100

x^{x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (x^{x} - 100)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{x}) - \frac{d}{d x} (100)

\frac{d}{d x} (x^{x}) = x^{x} (ln (x) + 1)

\frac{d}{d x} (100) = 0

= x^{x} (ln (x) + 1) - 0

Simplify

= x^{x} (ln (x) + 1)

\frac{( x + 6 )}{x}

ln (\frac{9}{x})

e^{x} - 2

\frac{w \cdot v t x ^{2} + x}{x ^{2} + 2 x + 7}

\frac{d}{d r} (3.14 r^{3})

What is the derivative of x^x-100 ?
The derivative of x^x-100 is x^x(ln(x)+1)
What is the first derivative of x^x-100 ?
The first derivative of x^x-100 is x^x(ln(x)+1)