What is the first derivative of 2x-y+1 ?

The first derivative of 2x-y+1 is 2

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derivative of 2x-y+1

derivative of

2 x - y + 1

2

Solution steps

\frac{d}{d x} (2 x - y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d y}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x) = 2

\frac{d y}{d x} = 0

\frac{d}{d x} (1) = 0

= 2 - 0 + 0

Simplify

= 2

2 x - y

t \cdot lo g_{10} (2 t)

2 t^{2} e^{- t}

\frac{( x ^{2} + 1 )}{( 1 - x )}

\frac{d}{d t} (30 + 2 t)