What is the derivative of y=tan(-x+1) ?

The derivative of y=tan(-x+1) is -sec^2(-x+1)

What is the first derivative of y=tan(-x+1) ?

The first derivative of y=tan(-x+1) is -sec^2(-x+1)

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derivative of

y = tan (- x + 1)

- sec^{2} (- x + 1)

Solution steps

\frac{d}{d x} (tan (- x + 1))

Apply the chain rule:

sec^{2} (- x + 1) \frac{d}{d x} (- x + 1)

= sec^{2} (- x + 1) \frac{d}{d x} (- x + 1)

\frac{d}{d x} (- x + 1) = - 1

= sec^{2} (- x + 1) (- 1)

Simplify

= - sec^{2} (- x + 1)

\frac{d}{d x} ((x^{2} - 2) (m - n) - 2 m + 2 n)

2^{x} - x^{2}

(x^{2} + 3 x)^{5}

\frac{d}{d x} (\frac{( 4 x - y )}{( 2 x + y )})

sin (x^{\frac{1}{2}})

What is the derivative of y=tan(-x+1) ?
The derivative of y=tan(-x+1) is -sec^2(-x+1)
What is the first derivative of y=tan(-x+1) ?
The first derivative of y=tan(-x+1) is -sec^2(-x+1)