What is the derivative of x^2-y^2 ?

The derivative of x^2-y^2 is 2x

What is the first derivative of x^2-y^2 ?

The first derivative of x^2-y^2 is 2x

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derivative of

x^{2} - y^{2}

2 x

Solution steps

\frac{d}{d x} (x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (y^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

\frac{1}{( x + 2 ) ^{2}}

\frac{( x - m ^{2} )}{( x + 1 )}

\frac{d}{d t} (5 - 6 t + t^{2})

\frac{d}{d t} (3 e^{s i n (0.5 t)} - 4)

\frac{d}{d x} (- (cos^{2} (x) + cos^{2} (y)) 2)