What is the derivative of 2x^3-15x^2+36x+6 ?

The derivative of 2x^3-15x^2+36x+6 is 6x^2-30x+36

What is the first derivative of 2x^3-15x^2+36x+6 ?

The first derivative of 2x^3-15x^2+36x+6 is 6x^2-30x+36

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derivative of

2 x^{3} - 15 x^{2} + 36 x + 6

6 x^{2} - 30 x + 36

Solution steps

\frac{d}{d x} (2 x^{3} - 15 x^{2} + 36 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (15 x^{2}) + \frac{d}{d x} (36 x) + \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (15 x^{2}) = 30 x

\frac{d}{d x} (36 x) = 36

\frac{d}{d x} (6) = 0

= 6 x^{2} - 30 x + 36 + 0

Simplify

= 6 x^{2} - 30 x + 36

x^{6} + 3 x^{2} - 9

\frac{1}{x ^{2} + b}

(\frac{u}{v})^{2}

y = \frac{cot ( x )}{( 1 + cot ( x ) )}

\frac{d}{d a} (\frac{( sin ^{2} ( a ) )}{( 1 + cos ^{2} ( a ) )})

What is the derivative of 2x^3-15x^2+36x+6 ?
The derivative of 2x^3-15x^2+36x+6 is 6x^2-30x+36
What is the first derivative of 2x^3-15x^2+36x+6 ?
The first derivative of 2x^3-15x^2+36x+6 is 6x^2-30x+36