What is the derivative of 5x^3+16b^2 ?

The derivative of 5x^3+16b^2 is 15x^2

What is the first derivative of 5x^3+16b^2 ?

The first derivative of 5x^3+16b^2 is 15x^2

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derivative of

5 x^{3} + 16 b^{2}

15 x^{2}

Solution steps

\frac{d}{d x} (5 x^{3} + 16 b^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (16 b^{2})

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (16 b^{2}) = 0

= 15 x^{2} + 0

Simplify

= 15 x^{2}

y = \frac{( x + 2 ) ^{2}}{x}

f (\frac{1}{x ^{4}})

\frac{( e ^{x} - 1 )}{x}

y = x^{3} - x^{2} + x - 1

\frac{4}{( x - 1 )}

What is the derivative of 5x^3+16b^2 ?
The derivative of 5x^3+16b^2 is 15x^2
What is the first derivative of 5x^3+16b^2 ?
The first derivative of 5x^3+16b^2 is 15x^2