What is the derivative of 1/(cos(2x)) ?

The derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2

What is the first derivative of 1/(cos(2x)) ?

The first derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2

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derivative of

\frac{1}{cos ( 2 x )}

sec (2 x) tan (2 x) \cdot 2

Solution steps

\frac{d}{d x} (\frac{1}{cos ( 2 x )})

Simplify

\frac{1}{cos ( 2 x )} : sec (2 x)

= \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= sec (2 x) tan (2 x) \cdot 2

5 \cdot sin^{2} (x) - 8 \cdot cos^{5} (x)

\frac{d}{d x} (x^{5} \cdot a + x^{5} \cdot b - a - b)

(x^{2} + 5 x) 5

2 - ∣ 3 - x ∣

5 t^{4}

What is the derivative of 1/(cos(2x)) ?
The derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2
What is the first derivative of 1/(cos(2x)) ?
The first derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2