What is (\partial)/(\partial x)(-9ysin(3x)) ?

The answer to (\partial)/(\partial x)(-9ysin(3x)) is -27ycos(3x)

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(\partial)/(\partial x)(-9ysin(3x))

\frac{\partial}{\partial x} (- 9 y sin (3 x))

- 27 y cos (3 x)

Solution steps

\frac{\partial}{\partial x} (- 9 y sin (3 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 y \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 9 y cos (3 x) \cdot 3

Simplify

= - 27 y cos (3 x)

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\frac{d}{d x} (\frac{- 1}{( x + 1 ) ^{2}})

2 x^{2} + x

\int \frac{8 x ^{2}}{( 1 - x ^{3} ) ^{3}} d x

What is (\partial)/(\partial x)(-9ysin(3x)) ?
The answer to (\partial)/(\partial x)(-9ysin(3x)) is -27ycos(3x)