What is the derivative of y=4sec(2x) ?

The derivative of y=4sec(2x) is 8sec(2x)tan(2x)

What is the first derivative of y=4sec(2x) ?

The first derivative of y=4sec(2x) is 8sec(2x)tan(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 4 sec (2 x)

8 sec (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (4 sec (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 4 sec (2 x) tan (2 x) \cdot 2

Simplify

= 8 sec (2 x) tan (2 x)

\frac{( x ^{2} + 1 )}{2}

y = \frac{sin ^{3} ( x ) + 4}{3 cos ^{3} ( x )}

2 x^{3} - 2.5 x - 5

y = \frac{1}{( sin ( x ) + cos ( x ) )}

cos (6 - 2 x)

What is the derivative of y=4sec(2x) ?
The derivative of y=4sec(2x) is 8sec(2x)tan(2x)
What is the first derivative of y=4sec(2x) ?
The first derivative of y=4sec(2x) is 8sec(2x)tan(2x)