What is the derivative of (xy-1^2) ?

The derivative of (xy-1^2) is 2(xy-1)(x(dy)/(dx)+y)

What is the first derivative of (xy-1^2) ?

The first derivative of (xy-1^2) is 2(xy-1)(x(dy)/(dx)+y)

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Popular >

\frac{d}{d x} ((x y - 1)^{2})

2 (x y - 1) (x \frac{d y}{d x} + y)

Solution steps

\frac{d}{d x} ((x y - 1)^{2})

Apply the chain rule:

2 (x y - 1) \frac{d}{d x} (x y - 1)

= 2 (x y - 1) \frac{d}{d x} (x y - 1)

\frac{d}{d x} (x y - 1) = x \frac{d y}{d x} + y

= 2 (x y - 1) (x \frac{d y}{d x} + y)

ln ((2 x - 3)^{2})

(\frac{1}{x}) (x^{2} - 2)

sin (x^{\frac{1}{3}})

\frac{d}{dd} (\frac{1}{( d + d ^{'} )})

5 (4 x - 3)^{- 1}

What is the derivative of (xy-1^2) ?
The derivative of (xy-1^2) is 2(xy-1)(x(dy)/(dx)+y)
What is the first derivative of (xy-1^2) ?
The first derivative of (xy-1^2) is 2(xy-1)(x(dy)/(dx)+y)