What is the derivative of 1/((2+x^2)) ?

The derivative of 1/((2+x^2)) is -(2x)/((2+x^2)^2)

What is the first derivative of 1/((2+x^2)) ?

The first derivative of 1/((2+x^2)) is -(2x)/((2+x^2)^2)

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derivative of

\frac{1}{( 2 + x ^{2} )}

- \frac{2 x}{( 2 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 + x^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 2 + x ^{2} ) ^{2}} \frac{d}{d x} (2 + x^{2})

= - \frac{1}{( 2 + x ^{2} ) ^{2}} \frac{d}{d x} (2 + x^{2})

\frac{d}{d x} (2 + x^{2}) = 2 x

= - \frac{1}{( 2 + x ^{2} ) ^{2}} \cdot 2 x

Simplify

- \frac{1}{( 2 + x ^{2} ) ^{2}} \cdot 2 x : - \frac{2 x}{( 2 + x ^{2} ) ^{2}}

= - \frac{2 x}{( 2 + x ^{2} ) ^{2}}

arccos (1 - 2 x)

2^{s i n (x + 202 2^{\circ})}

tan^{4} (5 x)

\frac{1}{( x ) ^{\frac{1}{2}}}

\frac{2}{( x - 3 )}

What is the derivative of 1/((2+x^2)) ?
The derivative of 1/((2+x^2)) is -(2x)/((2+x^2)^2)
What is the first derivative of 1/((2+x^2)) ?
The first derivative of 1/((2+x^2)) is -(2x)/((2+x^2)^2)