What is the derivative of (5+3cos(x))(1-4tan(x)) ?

The derivative of (5+3cos(x))(1-4tan(x)) is -3sin(x)(1-4tan(x))-4sec^2(x)(5+3cos(x))

What is the first derivative of (5+3cos(x))(1-4tan(x)) ?

The first derivative of (5+3cos(x))(1-4tan(x)) is -3sin(x)(1-4tan(x))-4sec^2(x)(5+3cos(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(5 + 3 cos (x)) (1 - 4 tan (x))

- 3 sin (x) (1 - 4 tan (x)) - 4 sec^{2} (x) (5 + 3 cos (x))

Solution steps

\frac{d}{d x} ((5 + 3 cos (x)) (1 - 4 tan (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 5 + 3 cos (x), g = 1 - 4 tan (x)

= \frac{d}{d x} (5 + 3 cos (x)) (1 - 4 tan (x)) + \frac{d}{d x} (1 - 4 tan (x)) (5 + 3 cos (x))

\frac{d}{d x} (5 + 3 cos (x)) = - 3 sin (x)

\frac{d}{d x} (1 - 4 tan (x)) = - 4 sec^{2} (x)

= (- 3 sin (x)) (1 - 4 tan (x)) + (- 4 sec^{2} (x)) (5 + 3 cos (x))

Simplify

= - 3 sin (x) (1 - 4 tan (x)) - 4 sec^{2} (x) (5 + 3 cos (x))

(x - 2) (\frac{1}{x + 2}) (x^{3})

y = (x + x^{2})^{\frac{1}{2}}

(s - 1)^{n} \cdot t

\frac{( ( 2 x - 1 ) ^{2} )}{( ( x + 2 ) ^{3} )}^{^{'}}

lo g_{10} (sin (x^{2}))

What is the derivative of (5+3cos(x))(1-4tan(x)) ?
The derivative of (5+3cos(x))(1-4tan(x)) is -3sin(x)(1-4tan(x))-4sec^2(x)(5+3cos(x))
What is the first derivative of (5+3cos(x))(1-4tan(x)) ?
The first derivative of (5+3cos(x))(1-4tan(x)) is -3sin(x)(1-4tan(x))-4sec^2(x)(5+3cos(x))