What is the first d/(do)(modx^2) ?

The first d/(do)(modx^2) is mdx^2

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d/(do)(modx^2)

\frac{d}{d o} (m o d x^{2})

m d x^{2}

Solution steps

\frac{d}{d o} (m o d x^{2})

Treat

m, d, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m d x^{2} \frac{d o}{d o}

Apply the common derivative:

\frac{d o}{d o} = 1

= m d x^{2} \cdot 1

Simplify

= m d x^{2}

y = (3 + 2 x^{2})^{4}

5^{2 x^{2} + x + 1}

(x^{2} + 3 x + 3)^{- 3}

\frac{e ^{x}}{( e ^{x} + 1 )}

sin^{3} (x) + cos^{2} (x)