What is the derivative of y=(x+1)(x+2)(x-3) ?

The derivative of y=(x+1)(x+2)(x-3) is 3x^2-7

What is the first derivative of y=(x+1)(x+2)(x-3) ?

The first derivative of y=(x+1)(x+2)(x-3) is 3x^2-7

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derivative of

y = (x + 1) (x + 2) (x - 3)

3 x^{2} - 7

Solution steps

\frac{d}{d x} ((x + 1) (x + 2) (x - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = (x + 2) (x - 3)

= \frac{d}{d x} (x + 1) (x + 2) (x - 3) + \frac{d}{d x} ((x + 2) (x - 3)) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} ((x + 2) (x - 3)) = 2 x - 1

= 1 \cdot (x + 2) (x - 3) + (2 x - 1) (x + 1)

Simplify

1 \cdot (x + 2) (x - 3) + (2 x - 1) (x + 1) : 3 x^{2} - 7

= 3 x^{2} - 7

4 t^{2} - 15 t + 25

\frac{x ^{4}}{9}

(x^{2} + x)^{x}

\frac{d}{d x} (ln (x^{2} + y^{2}) f (x, y))

cot (2 x + 1)

What is the derivative of y=(x+1)(x+2)(x-3) ?
The derivative of y=(x+1)(x+2)(x-3) is 3x^2-7
What is the first derivative of y=(x+1)(x+2)(x-3) ?
The first derivative of y=(x+1)(x+2)(x-3) is 3x^2-7