What is the derivative of y= 1/(2x) ?

The derivative of y= 1/(2x) is -1/(2x^2)

What is the first derivative of y= 1/(2x) ?

The first derivative of y= 1/(2x) is -1/(2x^2)

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derivative of

y = \frac{1}{2 x}

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

10 0^{200} x

3 x^{6} ln (3 x^{3})

e^{- 4} x - e^{- 2} x

\frac{( 2 x ^{2} + 5 x )}{( x )}

y = lo g_{10} (\frac{x + 1}{x})

What is the derivative of y= 1/(2x) ?
The derivative of y= 1/(2x) is -1/(2x^2)
What is the first derivative of y= 1/(2x) ?
The first derivative of y= 1/(2x) is -1/(2x^2)