What is the derivative of (3x+1)^3 ?

The derivative of (3x+1)^3 is 9(3x+1)^2

What is the first derivative of (3x+1)^3 ?

The first derivative of (3x+1)^3 is 9(3x+1)^2

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derivative of

(3 x + 1)^{3}

9 (3 x + 1)^{2}

Solution steps

\frac{d}{d x} ((3 x + 1)^{3})

Apply the chain rule:

3 (3 x + 1)^{2} \frac{d}{d x} (3 x + 1)

= 3 (3 x + 1)^{2} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 3 (3 x + 1)^{2} \cdot 3

Simplify

= 9 (3 x + 1)^{2}

\frac{d}{d x} (- x^{2} + 3 x + k)

y = (x^{- 2}) ln (x)

\frac{d}{d t} (4 cos^{3} (t))

\frac{( 1 )}{( x ^{n} + a ^{n} )}

sin^{2} (x) (cos (x))^{2}

What is the derivative of (3x+1)^3 ?
The derivative of (3x+1)^3 is 9(3x+1)^2
What is the first derivative of (3x+1)^3 ?
The first derivative of (3x+1)^3 is 9(3x+1)^2