What is the derivative of y=(x^3)/3-5(x^2)/2+6x-4 ?

The derivative of y=(x^3)/3-5(x^2)/2+6x-4 is x^2-5x+6

What is the first derivative of y=(x^3)/3-5(x^2)/2+6x-4 ?

The first derivative of y=(x^3)/3-5(x^2)/2+6x-4 is x^2-5x+6

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derivative of

y = \frac{x ^{3}}{3} - 5 \frac{x ^{2}}{2} + 6 x - 4

x^{2} - 5 x + 6

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - 5 \cdot \frac{x ^{2}}{2} + 6 x - 4)

Simplify

\frac{x ^{3}}{3} - 5 \cdot \frac{x ^{2}}{2} + 6 x - 4 : \frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 6 x - 4

= \frac{d}{d x} (\frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 6 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (\frac{5 x ^{2}}{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (4)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{5 x ^{2}}{2}) = 5 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (4) = 0

= x^{2} - 5 x + 6 - 0

Simplify

= x^{2} - 5 x + 6

y = \frac{2 ^{x}}{3 ^{x}}

\frac{d}{d t} (40 - 8 t)

x^{2} \cdot 1 + x^{2}

(3 x^{2} + 5)^{9}

\frac{d}{d x} (\frac{( x - y )}{y _{2} ( x )})

What is the derivative of y=(x^3)/3-5(x^2)/2+6x-4 ?
The derivative of y=(x^3)/3-5(x^2)/2+6x-4 is x^2-5x+6
What is the first derivative of y=(x^3)/3-5(x^2)/2+6x-4 ?
The first derivative of y=(x^3)/3-5(x^2)/2+6x-4 is x^2-5x+6