What is the d/(dt)(100+10t+1.25t) ?

The d/(dt)(100+10t+1.25t) is 11.25

What is the first d/(dt)(100+10t+1.25t) ?

The first d/(dt)(100+10t+1.25t) is 11.25

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\frac{d}{d t} (100 + 10 t + 1.25 t)

11.25

Solution steps

\frac{d}{d t} (100 + 10 t + 1.25 t)

Simplify

100 + 10 t + 1.25 t : 100 + 11.25 t

= \frac{d}{d t} (100 + 11.25 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (100) + \frac{d}{d t} (11.25 t)

\frac{d}{d t} (100) = 0

\frac{d}{d t} (11.25 t) = 11.25

= 0 + 11.25

Simplify

= 11.25

y = \frac{arcsin ( 1 )}{x}

\frac{( 1 - x ) x ^{2}}{( 1 + x ^{2} )}

\frac{d}{d x} ((x + z) (x - 5)^{8})

\frac{e ^{x}}{3}

y = \frac{x}{( x ^{2} - 3 )}

What is the d/(dt)(100+10t+1.25t) ?
The d/(dt)(100+10t+1.25t) is 11.25
What is the first d/(dt)(100+10t+1.25t) ?
The first d/(dt)(100+10t+1.25t) is 11.25