What is the derivative of y=1+3x-x^2 ?

The derivative of y=1+3x-x^2 is -2x+3

What is the first derivative of y=1+3x-x^2 ?

The first derivative of y=1+3x-x^2 is -2x+3

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derivative of

y = 1 + 3 x - x^{2}

- 2 x + 3

Solution steps

\frac{d}{d x} (1 + 3 x - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 x) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 3 - 2 x

Simplify

= - 2 x + 3

y = \frac{e ^{x} + sin ( x )}{2}

x^{1 - x}

y = x - 2

tan^{3} (\frac{x}{sin ( x )})

\frac{z - 1}{x ^{3}}

What is the derivative of y=1+3x-x^2 ?
The derivative of y=1+3x-x^2 is -2x+3
What is the first derivative of y=1+3x-x^2 ?
The first derivative of y=1+3x-x^2 is -2x+3