What is the derivative of y=x^3+e^7x ?

The derivative of y=x^3+e^7x is 3x^2+e^7

What is the first derivative of y=x^3+e^7x ?

The first derivative of y=x^3+e^7x is 3x^2+e^7

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derivative of

y = x^{3} + e^{7} x

3 x^{2} + e^{7}

Solution steps

\frac{d}{d x} (x^{3} + e^{7} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (e^{7} x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (e^{7} x) = e^{7}

= 3 x^{2} + e^{7}

sin^{2} (x) + 4

\frac{2 a}{y}

(\frac{7 x ^{3}}{2 x ^{2} + 1})^{3}

y = \frac{( 1 - x ^{3} )}{( 1 + x ^{3} )}

u^{2} + v^{2}

What is the derivative of y=x^3+e^7x ?
The derivative of y=x^3+e^7x is 3x^2+e^7
What is the first derivative of y=x^3+e^7x ?
The first derivative of y=x^3+e^7x is 3x^2+e^7