What is the derivative of ln(a*x^2+b) ?

The derivative of ln(a*x^2+b) is (2ax)/(ax^2+b)

What is the first derivative of ln(a*x^2+b) ?

The first derivative of ln(a*x^2+b) is (2ax)/(ax^2+b)

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\frac{d}{d x} (ln (a \cdot x^{2} + b))

\frac{2 a x}{a x ^{2} + b}

Solution steps

\frac{d}{d x} (ln (a x^{2} + b))

Apply the chain rule:

\frac{1}{a x ^{2} + b} \frac{d}{d x} (a x^{2} + b)

= \frac{1}{a x ^{2} + b} \frac{d}{d x} (a x^{2} + b)

\frac{d}{d x} (a x^{2} + b) = 2 a x

= \frac{1}{a x ^{2} + b} \cdot 2 a x

Simplify

\frac{1}{a x ^{2} + b} \cdot 2 a x : \frac{2 a x}{a x ^{2} + b}

= \frac{2 a x}{a x ^{2} + b}

sin^{4} (x) + sin (x^{4})

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\frac{2}{( 1 - x )}

(5 x + 4)^{5}

What is the derivative of ln(a*x^2+b) ?
The derivative of ln(a*x^2+b) is (2ax)/(ax^2+b)
What is the first derivative of ln(a*x^2+b) ?
The first derivative of ln(a*x^2+b) is (2ax)/(ax^2+b)