What is the derivative of y=2x^2-5x ?

The derivative of y=2x^2-5x is 4x-5

What is the first derivative of y=2x^2-5x ?

The first derivative of y=2x^2-5x is 4x-5

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derivative of

y = 2 x^{2} - 5 x

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

= 4 x - 5

x^{3} + x^{2} + x - 4

- t^{2} + 2 t

x^{3} tan (x)

\frac{d}{dd} (785 (d))

\frac{d}{d y} (0.2 (y - p))

What is the derivative of y=2x^2-5x ?
The derivative of y=2x^2-5x is 4x-5
What is the first derivative of y=2x^2-5x ?
The first derivative of y=2x^2-5x is 4x-5