What is the derivative of 3x^4+1 ?

The derivative of 3x^4+1 is 12x^3

What is the first derivative of 3x^4+1 ?

The first derivative of 3x^4+1 is 12x^3

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derivative of

3 x^{4} + 1

12 x^{3}

Solution steps

\frac{d}{d x} (3 x^{4} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (1) = 0

= 12 x^{3} + 0

Simplify

= 12 x^{3}

arctan (\frac{1}{2 x - 1})

\frac{x}{( x ^{2} - 1 ) ^{4}}

6 x^{2} y^{2}

- 4 x^{2} cos (x)

\frac{lo g _{10} ( 1 )}{x ^{3}}

What is the derivative of 3x^4+1 ?
The derivative of 3x^4+1 is 12x^3
What is the first derivative of 3x^4+1 ?
The first derivative of 3x^4+1 is 12x^3