What is the derivative of y= 1/((x+2)) ?

The derivative of y= 1/((x+2)) is -1/((x+2)^2)

What is the first derivative of y= 1/((x+2)) ?

The first derivative of y= 1/((x+2)) is -1/((x+2)^2)

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derivative of

y = \frac{1}{( x + 2 )}

- \frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= - \frac{1}{( x + 2 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 2 ) ^{2}}

\frac{x ^{7}}{7} + \frac{x ^{5}}{5} \frac{x ^{3}}{3} + x

5 cos^{2} (3 x)

u + 1

5^{x + 3}

x^{3} - x + 2

What is the derivative of y= 1/((x+2)) ?
The derivative of y= 1/((x+2)) is -1/((x+2)^2)
What is the first derivative of y= 1/((x+2)) ?
The first derivative of y= 1/((x+2)) is -1/((x+2)^2)