What is the derivative of log_{10}(1/(x^2)) ?

The derivative of log_{10}(1/(x^2)) is -2/(ln(10)x)

What is the first derivative of log_{10}(1/(x^2)) ?

The first derivative of log_{10}(1/(x^2)) is -2/(ln(10)x)

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derivative of

lo g_{10} (\frac{1}{x ^{2}})

- \frac{2}{ln ( 10 ) x}

Solution steps

\frac{d}{d x} (lo g_{10} (\frac{1}{x ^{2}}))

Simplify

lo g_{10} (\frac{1}{x ^{2}}) : - lo g_{10} (x^{2})

= \frac{d}{d x} (- lo g_{10} (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (lo g_{10} (x^{2}))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= - \frac{d}{d x} (\frac{ln ( x ^{2} )}{ln ( 10 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{ln ( 10 )} \frac{d}{d x} (ln (x^{2}))

Apply the chain rule:

\frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

= \frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - \frac{1}{ln ( 10 )} \cdot \frac{1}{x ^{2}} \cdot 2 x

Simplify

- \frac{1}{ln ( 10 )} \cdot \frac{1}{x ^{2}} \cdot 2 x : - \frac{2}{ln ( 10 ) x}

= - \frac{2}{ln ( 10 ) x}

sin^{2} (2 x + 0.5)

1 + a sin (x)

\frac{1}{x ^{3} - 3}

f (x) = tan (4 5^{\circ})

\frac{s ^{3} x}{cos ( x )}

What is the derivative of log_{10}(1/(x^2)) ?
The derivative of log_{10}(1/(x^2)) is -2/(ln(10)x)
What is the first derivative of log_{10}(1/(x^2)) ?
The first derivative of log_{10}(1/(x^2)) is -2/(ln(10)x)