What is the sum from n=2 to infinity of n/(n+2) ?

The sum from n=2 to infinity of n/(n+2) is diverges

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sum from n=2 to infinity of n/(n+2)

n = 2 \sum \infty \frac{n}{n + 2}

diverges

Solution steps

n = 2 \sum \infty \frac{n}{n + 2}

Apply Series Divergence Test:

diverges

= diverges

f (x) = \frac{x ^{2} + 3 x - 2}{x ^{2} - 5 x + 6}

f (x) = e^{x} - x^{3}

y^{^{''}} + 12 y^{^{'}} + 36 y = 0, y (1) = 0, y^{^{'}} (1) = - 1

y^{^{'}} = \frac{( x - y )}{( x + 2 y )}, y (0) = 1

\frac{d}{d x} (lo g_{e} (cos (4 x)))

What is the sum from n=2 to infinity of n/(n+2) ?
The sum from n=2 to infinity of n/(n+2) is diverges