What is the derivative of x(ln(x))^2-e ?

The derivative of x(ln(x))^2-e is ln^2(x)+2ln(x)

What is the first derivative of x(ln(x))^2-e ?

The first derivative of x(ln(x))^2-e is ln^2(x)+2ln(x)

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derivative of

x (ln (x))^{2} - e

ln^{2} (x) + 2 ln (x)

Solution steps

\frac{d}{d x} (x (ln (x))^{2} - e)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x (ln (x))^{2}) - \frac{d e}{d x}

\frac{d}{d x} (x (ln (x))^{2}) = ln^{2} (x) + 2 ln (x)

\frac{d e}{d x} = 0

= ln^{2} (x) + 2 ln (x) - 0

Simplify

= ln^{2} (x) + 2 ln (x)

(x^{x})^{3}

\frac{x}{x ^{3} + 1}

\frac{d}{d n} ((- i)^{4 n})

\frac{y ^{2}}{x ^{2}}

a^{3} - 3

What is the derivative of x(ln(x))^2-e ?
The derivative of x(ln(x))^2-e is ln^2(x)+2ln(x)
What is the first derivative of x(ln(x))^2-e ?
The first derivative of x(ln(x))^2-e is ln^2(x)+2ln(x)