What is the d/(dt)(5t^3-10t) ?

The d/(dt)(5t^3-10t) is 15t^2-10

What is the first d/(dt)(5t^3-10t) ?

The first d/(dt)(5t^3-10t) is 15t^2-10

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\frac{d}{d t} (5 t^{3} - 10 t)

15 t^{2} - 10

Solution steps

\frac{d}{d t} (5 t^{3} - 10 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t^{3}) - \frac{d}{d t} (10 t)

\frac{d}{d t} (5 t^{3}) = 15 t^{2}

\frac{d}{d t} (10 t) = 10

= 15 t^{2} - 10

4^{x} + 1

\frac{d}{d a} (\frac{a ^{2} - 2 a + a}{9})

y^{2} x + 5 x y^{3} + 10 y^{2} + 8 x y

\frac{d}{d a} (\frac{( cos ( a ) )}{( 1 - sin ( a ) )})

y = \frac{1}{( x ^{2} + 4 )}