What is the derivative of pi/x+ln(2) ?

The derivative of pi/x+ln(2) is -pi/(x^2)

What is the first derivative of pi/x+ln(2) ?

The first derivative of pi/x+ln(2) is -pi/(x^2)

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\frac{d}{d x} (\frac{π}{x} + ln (2))

- \frac{π}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{π}{x} + ln (2))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{π}{x}) + \frac{d}{d x} (ln (2))

\frac{d}{d x} (\frac{π}{x}) = - \frac{π}{x ^{2}}

\frac{d}{d x} (ln (2)) = 0

= - \frac{π}{x ^{2}} + 0

Simplify

= - \frac{π}{x ^{2}}

\frac{\partial}{\partial x} ((x)^{2} (y)^{4})

\frac{x}{x + 5}

\int (x^{2} - 2) d x

2 x^{2} - 7

8 y^{^{''}} + 26 y = 0

What is the derivative of pi/x+ln(2) ?
The derivative of pi/x+ln(2) is -pi/(x^2)
What is the first derivative of pi/x+ln(2) ?
The first derivative of pi/x+ln(2) is -pi/(x^2)