What is the derivative of f(x)=0.2x+0.03 ?

The derivative of f(x)=0.2x+0.03 is 0.2

What is the first derivative of f(x)=0.2x+0.03 ?

The first derivative of f(x)=0.2x+0.03 is 0.2

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derivative of

f (x) = 0.2 x + 0.03

0.2

Solution steps

\frac{d}{d x} (0.2 x + 0.03)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.2 x) + \frac{d}{d x} (0.03)

\frac{d}{d x} (0.2 x) = 0.2

\frac{d}{d x} (0.03) = 0

= 0.2 + 0

Simplify

= 0.2

(\frac{3}{2})^{x}

\frac{x ^{2}}{4 - x ^{2}}

ln (1 + cos (x))

\frac{d}{d a} (1 + 6 cos^{2} (a) + cos^{4} (a))

f (x) = x^{6} - x^{4} - 2

What is the derivative of f(x)=0.2x+0.03 ?
The derivative of f(x)=0.2x+0.03 is 0.2
What is the first derivative of f(x)=0.2x+0.03 ?
The first derivative of f(x)=0.2x+0.03 is 0.2