What is the derivative of 1/g ?

The derivative of 1/g is -1/(g^2)

What is the first derivative of 1/g ?

The first derivative of 1/g is -1/(g^2)

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derivative of

\frac{1}{g}

- \frac{1}{g ^{2}}

Solution steps

\frac{d}{d g} (\frac{1}{g})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d g} (g^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot g^{- 1 - 1}

Simplify

- 1 \cdot g^{- 1 - 1} : - \frac{1}{g ^{2}}

= - \frac{1}{g ^{2}}

(x - 2)^{3}

tan^{2} (x) - sin^{3} (x)

e^{x} + 3 x^{2}

lo g_{10} ((x + 1)^{2})

\frac{( x + 3 )}{2}