What is the derivative of a^3-b^3 ?

The derivative of a^3-b^3 is 3a^2

What is the first derivative of a^3-b^3 ?

The first derivative of a^3-b^3 is 3a^2

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derivative of

a^{3} - b^{3}

3 a^{2}

Solution steps

\frac{d}{d a} (a^{3} - b^{3})

Treat

b

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (a^{3}) - \frac{d}{d a} (b^{3})

\frac{d}{d a} (a^{3}) = 3 a^{2}

\frac{d}{d a} (b^{3}) = 0

= 3 a^{2} - 0

Simplify

= 3 a^{2}

y = 5 x^{- 4}

10 x - 6

\frac{( x + 2 )}{( x - 1 )}

\frac{a}{( a - t ) ^{2}}

cos (6 x + 2)

What is the derivative of a^3-b^3 ?
The derivative of a^3-b^3 is 3a^2
What is the first derivative of a^3-b^3 ?
The first derivative of a^3-b^3 is 3a^2