What is the derivative of x^2cos(log_{10}(x)) ?

The derivative of x^2cos(log_{10}(x)) is 2xcos(log_{10}(x))-(xsin(log_{10}(x)))/(ln(10))

What is the first derivative of x^2cos(log_{10}(x)) ?

The first derivative of x^2cos(log_{10}(x)) is 2xcos(log_{10}(x))-(xsin(log_{10}(x)))/(ln(10))

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derivative of

x^{2} cos (lo g_{10} (x))

2 x cos (lo g_{10} (x)) - \frac{x sin ( lo g _{10} ( x ) )}{ln ( 10 )}

Solution steps

\frac{d}{d x} (x^{2} cos (lo g_{10} (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (lo g_{10} (x))

= \frac{d}{d x} (x^{2}) cos (lo g_{10} (x)) + \frac{d}{d x} (cos (lo g_{10} (x))) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (lo g_{10} (x))) = - \frac{sin ( lo g _{10} ( x ) )}{ln ( 10 ) x}

= 2 x cos (lo g_{10} (x)) + (- \frac{sin ( lo g _{10} ( x ) )}{ln ( 10 ) x}) x^{2}

Simplify

2 x cos (lo g_{10} (x)) + (- \frac{sin ( lo g _{10} ( x ) )}{ln ( 10 ) x}) x^{2} : 2 x cos (lo g_{10} (x)) - \frac{x sin ( lo g _{10} ( x ) )}{ln ( 10 )}

= 2 x cos (lo g_{10} (x)) - \frac{x sin ( lo g _{10} ( x ) )}{ln ( 10 )}

\frac{d}{d t} (2 t - 2)

\frac{d}{d a} (sec^{2} (a) + tan^{2} (a))

y = 5 sin (x) + 3 cos (x) + 5 x^{2}

\frac{d}{d n} (i^{4 n + 1})

ln ((2 x + 3)^{2})

What is the derivative of x^2cos(log_{10}(x)) ?
The derivative of x^2cos(log_{10}(x)) is 2xcos(log_{10}(x))-(xsin(log_{10}(x)))/(ln(10))
What is the first derivative of x^2cos(log_{10}(x)) ?
The first derivative of x^2cos(log_{10}(x)) is 2xcos(log_{10}(x))-(xsin(log_{10}(x)))/(ln(10))