What is the derivative of 1-x^4e^{-8x} ?

The derivative of 1-x^4e^{-8x} is 8e^{-8x}x^4-4e^{-8x}x^3

What is the first derivative of 1-x^4e^{-8x} ?

The first derivative of 1-x^4e^{-8x} is 8e^{-8x}x^4-4e^{-8x}x^3

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derivative of

1 - x^{4} e^{- 8 x}

8 e^{- 8 x} x^{4} - 4 e^{- 8 x} x^{3}

Solution steps

\frac{d}{d x} (1 - x^{4} e^{- 8 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x^{4} e^{- 8 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{4} e^{- 8 x}) = 4 e^{- 8 x} x^{3} - 8 e^{- 8 x} x^{4}

= 0 - (4 e^{- 8 x} x^{3} - 8 e^{- 8 x} x^{4})

Simplify

= 8 e^{- 8 x} x^{4} - 4 e^{- 8 x} x^{3}

y = x^{4} - 3 x^{- 2} + 1

1 7^{x - 1}

\frac{d}{d b} (1 b)

\frac{5 + 1}{cos ( x )}

y = e^{x + 2 l n (x)}

What is the derivative of 1-x^4e^{-8x} ?
The derivative of 1-x^4e^{-8x} is 8e^{-8x}x^4-4e^{-8x}x^3
What is the first derivative of 1-x^4e^{-8x} ?
The first derivative of 1-x^4e^{-8x} is 8e^{-8x}x^4-4e^{-8x}x^3